Online Roulette Double Up System

The experienced roulette player will almost never apply a traditional betting system in the way it is depicted in various sources. The reason for this lies in the fact that all systems have limitations and potential traps, which have to be overcome. We should not that consistent winning is usually achieved with certain adjustments in the methods of play, with additional fine-tuning of system play.

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It became clear in the prior article, that the traditional Martingale system and its variations have a robust mathematical logic. However, the traditional system is not immune to drawbacks, which make it hazardous to play. One of these drawbacks is the restrained number of opportunities a player has to double his/her losing bets until the required wager grows far too much and reaches the table limit. Another disadvantage lies in that the amount, which is exposed to risk every time a string of losses occurs, grows considerably.

The ”Illusionary Bets”

However, there is a way to cushion the above mentioned drawbacks and it includes the application of the so called ”illusionary bets”. The latter represent zero-value bets, which are never placed for real. They are also known as ”null bets”, as a player does not have any money exposed to risk.

If we presume that the minimum bet is 5 units and the table maximum is 1000 units, the following series of losses may be expected before the limit is reached:

5 10 20 40 80 160 320 640

In case the eighth bet loses, it will be quite unpleasant situation and it may occur once every 170 ball spins, as we said in the previous article. Thus, we need to overcome such a situation. Let us assume that the moment we take our seat at the roulette table, six even-money outside bets are to be chosen from. During the prior wheel spin at least two or three of them turned out to be losers. In case a bet is made on one of the prior losers, this would mean it is the second bet in a potential series of losses. This way the first bet was an illusionary one, a null bet. It just extended the theoretical series of losses to nine bets, or a bit longer than before. We now have the following string:

0 5 10 20 40 80 160 320 640

Such a series of losses (9) may occur on average once every 323 spins. Thus, there has been an improvement of the situation.

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We may not make the first bet until one of the even-money bets lost two or three consecutive times. Let us presume that we abstain from placing the first bet until there have been three losses in a row. The theoretical series of losses will now include three null bets and will be as follows:

0 0 0 5 10 20 40 80 160 320 640

Such a series of losses (11) may occur on average once every 1 165 wheel spins, or it would be equal to 12-14 hours of play.

The Martingale System and Its Variations
Playing the Martingale System
The D’Alembert System
The Labouchere System
Playing the Labouchere System
Roulette Inside Bet System

The ”CYA Bets”

Cunning players have come up with another bet modification, known as the CYA bet. It represents a bet covering past losses and does not provide a player with any opportunity to score gains. The CYA bet is a more logical action than a double bet, because after a string of several consecutive losses, a player will look for compensation, instead of scoring a meager 5-unit gain.

When playing the Martingale system, a player should profit on winning bets and after a series of no more than three losses. Once a fourth or a fifth consecutive loss has been registered, he/she will need to shift its objective from making a profit to compensating for the string of losses. In doing so, a player will have a complementary wheel spin before the table limit is reached.

If we have three null bets and a CYA bet after the fourth loss, a table limit of 1000 units will not be encountered until the 12th loss. Or, we have the following series:

”CYA Bets”
Bet Number:123456789101112
Bet Amount:0005510204080160320640

The probability of twelve consecutive losses occurring is 1/2213 (once every 2213 ball spins). However, we should not forget that it may occur on the very next twelve ball spins.

In the past few years, a number of casinos have raised their maximum outside bet limits to $10 000 or even more. Given that figure, if we have three null bets and a CYA bet after the fourth loss, we would be able to double our losing bets 16 times. The probability of sixteen consecutive losses occurring is 1/28 844 (once every 28 844 ball spins). However, again it may occur on the very next sixteen ball spins.

The methods we discussed above are valid for the traditional Martingale system only. As far as the grand and the reverse variations of the Martingale are concerned, average players and, especially beginners, should better avoid using them. The reason for it lies in that there is no certain way to cushion the high levels of risk.

Thread Rating:

ademco
I don't care who knows about it and I'm not trying to sell it. I know some of the members on this site have coding expeariance as does the site owner and I just want someone to proove me wrong, if I am!
in a nutshell. On a normal roulette table there are several ways to bet, some of the odds are seemingly good (17-1 53-1) but I prefer the 2-1 bets, these are streets and the 12s. On a street (I believe im using this term right, I mean the pay lines at the back of the table as in the line 1 4 7 10 13 16 19 22 25 28 31 34) on each line you have a little less than 1/3 chance of winning. I believe I saw on one site a stat of 31.8%. The few times I have been to casinos with real roulette, I play two of them usually the outside two. If the ball lands on any one number on those two lines you win 2-1 which means you loose one bet and tripple the other giving you a gain of 1 betting unit per bet. If the stat I saw was right 31.8% this should mean that the odds if you pick two of them is 63.16%
You may loose several bets in a row to a ball landing on the one line you diddnt play or on 0 or 00 but overall this system statistically should win. Unless Im wrong.
If I am wrong please explain to me how using math, or a code test, I would appreciate the help in the event I am wrong but according to the math I dont think I am
RonC
Assuming your numbers are correct, let's take $2,000 to the casino and bet it $20 ($10 on two groups of 12) at a time for 100 bets...
We'll do them right in a row...63 wins followed by 37 losses...
Win 1 unit 63 of the time @ $20 a bet =Bet $1260 and return of $1890 with $740 remaining to bet from the original amount...now you have $2630
Lose 2 units 37 of the time @ $20 a bet = Lose $740...now you have $1890.
Even simplified like this, the house advantage is almost correct (within $5, based on the rounding)
This is a loser...can it win sometimes? Sure. It is still a loser...
heather
This is how James Bond played Roulette in the book (not movie) 'Casino Royale', so you're not the first to think of it. I've tried it a few times and it seemed boring and didn't make me any significant money.
I don't have anything that runs long-term projections for Roulette or I'd do those for you. I am guessing that it ends up being very close to the HE, though. If this system worked consistently, Roulette would have been modified to reduce its effectiveness by now.
RonC

This is how James Bond played Roulette in the book (not movie) 'Casino Royale', so you're not the first to think of it. I've tried it a few times and it seemed boring and didn't make me any significant money.
I don't have anything that runs long-term projections for Roulette or I'd do those for you. I am guessing that it ends up being very close to the HE, though. If this system worked consistently, Roulette would have been modified to reduce its effectiveness by now.


I played this way for several days in Las Vegas on one of our earlier trips. I would bet $25-$100 on two of the groups of 12. I lost a lot of money and had a host want to meet me. Unless you are a really high-level player at a low house edge game, meeting a host is not a good sign!!!
WASHOO2
Ignore the layout of the felt. Go by sections of the 0/00 wheel and then target those sections of 12 contiguous numbers on each side of the wheel.
Sometimes you will be betting the first and second dozen , the second and the third dozen , or the third and the first dozen.
Once you have mastered this you can go further and eliminate 2 numbers from the 24 pockets and operate on a reduced scale. It`s nly one number on each half of the wheel.
Just keep following the action of the wheel.
WASHOO2
MangoJ
Come on guys. the dozen bet pays 2:1, while the probability of a hit is 12/37 = 32.4%. This should not be too complicated, the dozen bet is negative EV (3*12/37 - 1 = -2.7%).
Playing two dozen bets does not change this very EV. If you play two dozen bets, the odds are 1:2, the probability of a hit is 24/37.
The EV of the combined bet is . Surprised ?
The two-dozen bet is as good (or as bad) as any other bet you make. The only thing it chances is variance. But if you want low variance, why don't you play the triple dozen bet ?
MakingBook
I have an online casino that I offer to all my players.Roulette systems and methods
I would be thrilled if they would use the system.
'I am a man devoured by the passion for gambling.' --Dostoevsky, 1871
ahiromu
First time I was in Vegas, I'd play two 12-sets at a time for $25 each and leave when I made $50. It went very well.
Last night, I bought in for $20 and put $3 down on 6 numbers and $2 elsewhere. It hit 00. Fuck roulette.
Its - Possessive; It's - 'It is' / 'It has'; There - Location; Their - Possessive; They're - 'They are'
Wizard
Administrator
I wonder which is more:
A. Number of players to believe they have a long-term winning betting system.
B. Number of players to believe they could invent a casino game equal or better to what is out there now.
C. Number of players to believe both A and B.
D. Number of times somebody has remarked 'The hard part is keeping the weight off' in the HB challenge thread.
It's not whether you win or lose; it's whether or not you had a good bet.
CrapsForever
My wife (Who hates gambling) has played Roulette 7 total times and won 5 times with the same number in 3 different countries: The #17
What are the odds of that???

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Last victory was last Saturday. Next time, I'm in a Casino with her; I'm putting $100 straight-up on the #17.

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Craps is the most 'Jekyll and Hyde' casino game ever invented!